How to show contact of a person in Persons navigator?
The specifics of this calculated attribute is that the contact mechanism type is enum.
Its values and codes are as follows:
| Member name | Value | Description |
|---|---|---|
| Address | 0 | Address value. Stored as 'A'. |
| 1 | Mail value. Stored as 'E'. | |
| Fax | 2 | Fax value. Stored as 'F'. |
| MobilePhone | 3 | MobilePhone value. Stored as 'M'. |
| Other | 4 | Other value. Stored as 'O'. |
| Telephone | 5 | Telephone value. Stored as 'T'. |
| WebSite | 6 | WebSite value. Stored as 'W'. |
Let's say you need to get a column with email addresses.
The repositiry of the calculated attribute would be "General.Contacts.Parties" and it would have the following expressions:
10:GETOBJVALUE EXP:20 ATTRIB:Name
20:GETOBJVALUE EXP:30 REF:ContactMechanism
30:FIRST EXP:40
40:FILTER CHILD:ContactMechanisms EXP:50
50:EQUAL EXP:60 CONST:1
60:CAST EX:70 CONST:System.Int32
70:GETOBJVALUE REF:ContactMechanism ATTRIB:ContactMechanismType
Explanation:
- 10: get the value of the Name attribute from EXP:20
- 20: get the referent object ContactMechanism of EXP:30
- 30: get the first value of the list returned by EXP:40
- 40: filter the list of records in the child table ContactMechanisms by the conditions in EXP:50
- 50: check if EXP:60 is equal to 1 (1 = email)
- 60: cast EXP:70 which contains the ContactMechanismType to integer
- 70: get the value of the attribute ContactMechanismType from the referent object ContactMechanism
Notes If a person has more than one email, the attribute will return a random one. If a specific email is needed, more filters could be applied. If the person has no emails, the attribute will return an error. If you want to avoid that, you need to couny the records in the CHILD:ContactMechanisms first, and to try to get the email only if the records are more than one.